If $f(x) = \frac { (4x+3) } { (6x-4) }, x \neq \frac {2} {3}$, show that $f(x) =x$, for all $x \neq \frac {2} {3}$. What is the inverse of $f$

Question

$\begin{array}{1 1} f \; itself \\ x^{-1} \\\big(\large \frac { (4x+3) } { (6x+4) }\big)^{-1}\\ \large \frac {(6x-4) }{(4x+3)}\end{array}$