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Questions  >>  EAMCET  >>  Mathematics
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The solution of (1+x2)dydx+2xy4x2=0 is :

(a)3x(1+y2)=4y3+c(b)3y(1+x2)=4x3+c(c)3x(1y2)=4y3+c(d)3y(1+y2)=4x3+c
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