Q)
(chatquestion)...3.78. Near the point A (Fig. 3.10) lying on the boundary between
glass and vacuum the electric field strength in vacuum is equal to
10.0 V/m, the angle between the vector E, and the normal
E,
n of the boundary line being equal to a, = 30°. Find the field streng
E in glass near the point A, the angle a between the vector E and a
as well as the surface density of the bound charges at the point A.
319. Near the nlane e
%3D
Eo
Fig. 3.10.
1 Answer
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