(chatquestion)...5. If fesccx (sec x tan x f(x) + (sec x tan x + sec?x)) dr esecx Ax) + C, then a possible choice of f(x) is 1 (b) xsecx+ tan x+- 2 %3D 1 (a) secx+tan x+- 1 (d) secx-tan x - 2 1 (c) secx+xtan x-- 2

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