$Solute + H_2O \rightleftharpoons solution; \Delta H=\pm x$ For the given equation, Solubility(S) of a solute in the solvent (say $H_2O$) is given by $S = A e^{-\frac{\Delta H}{RT}}$ For a given solution, variation of log S with temperature is shown graphically. Hence, Solute is:

Question

(a) $CuSO_4.5H_2O$

(b) NaCl

(c) Sucrose

(d) CaO