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The radius of the circle passing through the centre of the inscribed circle of the $\Delta$le ABC and through the end point of the base BC is R then $\large\frac{a}{R}$$\sec \large\frac{A}{2}$ is equal to

$(a)\;3\qquad(b)\;4\qquad(c)\;2\qquad(d)\;0$

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