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Questions  >>  JEEMAIN and NEET  >>  Mathematics  >>  Class12  >>  Determinants
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If $a>0$ and determinant of $ax^2+2bx+c$ is -ve then $\begin{vmatrix}a&b&ax+b\\b&c&bx+c\\ax+b&bx+c&0\end{vmatrix}$ is equal to

$\begin{array}{1 1}(a)\;+ve&(b)\;(ac-b^2)(ax^2+2bx+c)\\(c)\;-ve&(d)\;0\end{array}$

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