If $1,\omega,\omega^2$ are the cube roots of unity ,then $\Delta=\begin{vmatrix}1&\omega^n&\omega^{2n}\\\omega^{2n}&1&\omega^n\\\omega^{2n}&1&\omega^n\end{vmatrix}$ is equal to

Question

$(a)\;\omega^2\qquad(b)\;0\qquad(c)\;1\qquad(d)\;\omega$