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Questions  >>  JEEMAIN and NEET  >>  Mathematics  >>  Class12  >>  Determinants
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If $C=2\cos \theta$ then the value of the determinant $\Delta=\begin{vmatrix}c&1&0\\1&c&1\\6&1&c\end{vmatrix}$ is

$\begin{array}{1 1}(a)\;\large\frac{2\sin^2\theta}{\sin \theta}&(b)\;8\cos^3\theta-4\cos\theta+6\\(c)\;\large\frac{2\sin 2\theta}{\sin \theta}&(d)\;8\cos^3\theta+4\cos \theta+6\end{array}$

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