AB and CD are two identical rods each of length l and mass m joined to form a cross. The moment of inertia of three two rods about a bisector XY of angles between the rods is

Question

$\begin{array}{1 1} (a)\;\frac{ml^2}{12} & \quad (b)\;\frac{ml^3}{3} \\ (c)\;\frac{2ml}{3} & \quad (d)\;\frac{ml^2}{6} \end{array}$