Find $ \frac {dy}{dx} $ in the following: $ y = sin^{-1} \left(\frac{2x}{1 + x^2}\right) $

Question

$\begin{array}{1 1} \large \frac{2}{1+x^2} \\ \large \frac{2x}{1+x^2}\\ -\large \frac{2}{1+x^2} \\ -\large \frac{2x}{1+x^2} \end{array} $