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Questions  >>  JEEMAIN and NEET  >>  Chemistry  >>  Equilibrium
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Q)

For a concentrated solution of a weak electrolytic $A_xB_y$ of concentration C, the degree of dissociation $\alpha$ is given by

(a) $\alpha = \sqrt{\frac{K_{eq}}{(x+y)}}$

(b) $\alpha = (\frac{K_{eq}}{C^{x+y-1} X^x Y^y})^{\frac{1}{x + y}}$

(c) $\alpha = \frac{k_{eq}}{C^{xy}}$

(d) $\alpha = \sqrt{\frac{K_{eq} C}{x \times y}}$

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