A particle is projected at time $t=0$ from a point P on the ground with a speed $V_0$ at an angle of $45^{\circ}$ to the horizontal . What is the magnitude of the angular momentum of the particle about point P at time $t= \large\frac{V_0}{g}$

Question

$$\begin {array} {1 1} (a)\;\frac{mV_0^2}{2 \sqrt 2 g} & \quad (b)\;\frac{mV_0^3}{\sqrt 2 g} \\ (c)\;\frac{mV_0^2}{\sqrt 2 g} & \quad  (d)\;\frac{mV_0^3}{2 \sqrt 2 } \end {array}$$