: If the given lines $\frac{x-1}{-3} = \frac{y-2}{2k} = \frac{z-3}{2}$ and $\frac{x-1}{3k} = \frac{y-1}{1} = \frac{z-6}{-5}$ are perpendicular, then k is $$\begin{array} (A)\: -10 \quad & (B) \: \frac{10}{7} \\ (C)\: \frac{-10}{7} \quad & (D)\: \frac{-7}{10} \end{array}$$

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