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Questions  >>  JEEMAIN and NEET  >>  Physics  >>  Class11  >>  Oscillations
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The phase constant in rad/sec of a simple pendulum whose amplitude of oscillation is 'b', initial displacement is 'y', initial velocity is 'v', frequency in rad/sec is 'w' is

$\begin{array}{1 1}(a)\;\frac{y}{b}\\(b)\;(\frac{y}{b}-\frac{v}{w}) \\( c)\;(\frac{y}{b}+\frac{v}{w}) \\(d)\;\frac{(y*v)}{(b*w)} \end{array}$

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