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JEEMAIN and NEET
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Chemistry
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Redox Reactions
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Calculate EMF of cell Pt,$H_2(1\;atm)/CH_3COOH(0.1M)\parallel NH_3(aq)(0.01N)/H_2\;atm$.Given :$K_a(CH_3COOH)=1.8\times 10^{-5},K_b(NH_3)=1.8\times 10^{-5}$
$\begin{array}{1 1}(a)\;0.45V\\(b)\;-0.45V\\(c)\;0.90V\\(d)\;-0.90V\end{array}$
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