$E_{cell}$ for reduction $NO_3^-\rightarrow NO$ by $Ag(s)$?

Question

$E^o_{Ag^+/Ag}=0.79$volt

$E^o_{NO_3^-/NO}=1$volt

$E^o_{NO_3^-/NO_2}=0.82$volt

$298\large\frac{RT}{F}$$=0.06$volt

$P_{NO_2}=P_{NO}=10^{-3}$

T=298K

$[Ag^+]=0.2M$

$[HNO_3]=1.5M$

$\begin{array}{1 1}(a)\;0.24v\\(b)\;0.25v\\(c)\;0.3v\\(d)\;0.27v\end{array}$