The EMF of cell $Ag,AgCl$ in 0.1M $KCl\parallel sat\;NH_4NO_3\parallel 0.1M\;AgNO_3,Ag$ is $0.45\;volt$ at $25^oC$.Calculate solubility product & solubility of $AgCl(0.1M\; KCl$ is $85\% $dissociated & $0.1M$ $AgNO_3$ is $82\%$ dissociated)

Question

$\begin{array}{1 1}(a)\;1.8\times 10^{-10},1.7\times 10^{-3}\\(b)\;1.7\times 10^{-10},1.8\times 10^{-3}\\(c)\;1.9\times 10^{-3},1.6\times 10^{-9}\\(d)\;1.2\times 10^{-9},1.6\times 10^{-3}\end{array}$