$I_1= \int \limits_{(-2-k)}^{k+3} x f[x (1-x)].dx; \; I_2= \int \limits_{(-2-k)}^{k+3} x f[x (1-x)].dx; \; \large\frac{I_1}{I_2}=?$

Question

\[\begin {array} {1 1} (a)\;\frac{1}{2} \\ (b)\;\frac{3}{2} \\ (c)\;\frac{1}{4} \\ (d)\;2 \end {array}\]