The rate law for a reaction $A\rightarrow B$ is rate=$K[A]^m[B]^n$.On tripling the concentration of A and halving the concentration of B,the ratio of new rate to the earlier rate of the reaction will be as

Question

$\begin{array}{1 1}(a)\;\large\frac{3^m}{2^n}&(b)\;\large\frac{2^n}{3^m}\\(c)\;\large\frac{3^n}{2^m}&(d)\;\large\frac{2^m}{3^n}\end{array}$