Email
Chat with tutors
Login
Ask Questions, Get Answers
Menu
X
home
ask
tuition
questions
practice
papers
mobile
tutors
pricing
X
Questions
>>
JEEMAIN and NEET
>>
Chemistry
Next similar question
Answer
Comment
Share
Q)
On the basis of the following
E
∘
values, the strongest oxidizing agent is :
[
F
e
(
C
N
6
)
]
4
−
→
[
F
e
(
C
N
6
)
]
3
−
+
e
−
1
;
E
∘
=
−
0.35
V
F
e
2
+
→
F
e
3
+
+
e
−
1
;
E
∘
=
−
0.77
V
(
1
)
[
F
e
(
C
N
6
)
]
3
−
(
2
)
[
F
e
(
C
N
6
)
]
4
−
(
3
)
F
e
2
+
(
4
)
F
e
3
+
Share
Please
log in
or
register
to add a comment.
Please
log in
or
register
to answer this question.
Next Similar Question >
Home
Ask
Tuition
Questions
Practice
Your payment for
is successful.
Continue
...
Please Wait