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JEEMAIN and NEET
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Mathematics
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Limit, Continuity and Differentiability
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Let $f : R\rightarrow [0,\infty]$ be such that $\lim\limits_{x\to 5}f(x)$ exists and $\lim\limits_{x\to 5}\large\frac{(f(x))^2-9}{\sqrt{|x-5|}}$ = 0. Then $\lim\limits_{x\to 5}f(x)$ equals
$(a)\;0\qquad(b)\;1\qquad(c)\;2\qquad(d)\;3$
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