Integrate : $\int \large\frac{\sqrt {\cos^{-1}(4x)}}{\sqrt {1-16x^2}}$$dx$

Question

$(a)\;-\frac{1}{6} \sqrt {\frac{\pi}{2} - \sin ^{-1} (4x)}+\cos ^{-1}x+c \qquad(b)\;-\frac{1}{6} \sqrt {\frac{\pi}{2} - \sin ^{-1} (4x)}+c \qquad(c)\;\sqrt { \sin ^{-1} (4x)} \qquad (d)\;None$