The threshold frequency for a certain metal is $3.3 \times 1014Hz$. If light of frequency $8.2 \times 1014 Hz$ is incident on the metal, predict the cutoff voltage for the photoelectric emission.

Question

$\begin {array} {1 1} (a)\;20.292V & \quad (b)\;20292 \times 10^{-4}kV \\ (c)\;202.92V & \quad (d)\;2.0292V \end {array}$