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CBSE XII
>>
Math
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Continuity and Differentiability
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Q)
Find
d
y
d
x
in the following:
y
=
sin
−
1
(
2
x
√
1
−
x
2
)
,
−
1
√
2
<
x
<
1
√
2
d
y
d
x
=
−
2
√
1
−
x
2
d
y
d
x
=
2
√
1
+
x
2
d
y
d
x
=
2
√
1
−
x
3
d
y
d
x
=
2
√
1
−
x
2
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