# If the function $f(x)=\left\{\begin{array}{1 1}\large\frac{x^2-(A+2)x+A}{x-2}&x\neq 2\\2&x=2\end{array}\right.$ is continuous at $x=2$ then
$(a)\;A=0\qquad(b)\;A=1\qquad(c)\;A=-1\qquad(d)\;None\;of\;these$