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Q)

$\lim\limits_{x\to\Large\frac{\pi}{6}}\large\frac{3\sin x-\sqrt 3\cos x}{6x-\pi}$ equals

$(a)\;\sqrt 3\qquad(b)\;\large\frac{1}{\sqrt 3}$$\qquad(c)\;-\sqrt 3\qquad(d)\;\large\frac{-1}{\sqrt 3}$

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