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We wish to see inside an atom. Assuming the atom to have a diameter of 100 pm, this means that one must be able to resolve a width of say 10 pm. If an electron microscope is used, the minimum electron energy required is about

$\begin {array} {1 1} (a)\;1.5\: KeV & \quad (b)\;15\: KeV \\ (c)\;150\: KeV & \quad (d)\;1.5\: MeV \end {array}$

 

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