The energy of a photon is equal to the KE of a proton. The energy of the photon is E. Let $ \lambda_1$ be the de- Broglie wavelength of the proton and $ \lambda_2$ be the wavelength of the photon. So, $\large\frac{\lambda_1}{\lambda_2}$ is

Question

$\begin {array} {1 1} (a)\;E^0 & \quad (b)\;E^{\large\frac{1}{2}} \\ (c)\;E^{-1} & \quad (d)\;E^{-2} \end {array}$