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The function $f:R\{0\}\rightarrow R$ given by $f(x)=\large\frac{1}{x}-\frac{2}{e^{2x}-1}$ can be made continuous at $x=0$ by defining f(0) as

$(a)\;0\qquad(b)\;1\qquad(c)\;2\qquad(d)\;-1$

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