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JEEMAIN and NEET
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Mathematics
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Limit, Continuity and Differentiability
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The function $f:R\{0\}\rightarrow R$ given by $f(x)=\large\frac{1}{x}-\frac{2}{e^{2x}-1}$ can be made continuous at $x=0$ by defining f(0) as
$(a)\;0\qquad(b)\;1\qquad(c)\;2\qquad(d)\;-1$
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