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25ml of a solution of $Na_2CO_3$ having a specific gravity of $1.25ml^{-1}$ required 32.9ml of a solution of HCl containing 109.5g of the acid per litre for complete neutralization .Calculate the volume of 0.84N $H_2SO_4$ that will be completely neutralized by 125g of $Na_2CO_3$ solution.

$(a)\;350ml\qquad(b)\;470ml\qquad(c)\;225ml\qquad(d)\;330ml$

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