$(a)\:\large\frac{x-2}{4}=\frac{y+1}{1}=\frac{z+1}{1}\:\qquad\:(b)\:\large\frac{x+2}{4}=\frac{y-1}{1}=\frac{z-1}{3}\:\qquad\:(c)\:\large\frac{x-2}{-1}=\frac{y+1}{1}=\frac{z+1}{3}\:\qquad\:(d)\:\large\frac{x+2}{-1}=\frac{y-1}{1}=\frac{z-1}{3}$