12√(x−1)(x−2)(x−8)(x−4)(x−7)[1x−1+1x−2−1x−3−1x−4−1x−5]12√(x−1)(x−2)(x−3)(x−4)(x−5)[1x+1+1x−2−1x+3−1x−4−1x−5]12√(x−1)(x−2)(x−3)(x−4)(x−5)[1x−1+1x−2−1x−3−1x−4−1x−5]14√(x−1)(x−2)(x−3)(x−4)(x−5)[1x−1+1x−2−1x−3−1x−4−1x−5]