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A charge Q is placed at a distance $D( > R)$ above the centre of disk of radius R The magnitude of flux through disk is $\phi$ . Now a hemispherical shell of radius R is put above the disk to form a closed surface. The flux through the closed surface, if direction of area vector along outward normal is +ve, is :

$(A)\;-\phi \\ (B)\;\frac{-\phi D}{R} \\ (C)\; \phi \\ (D)\;\frac{\phi R}{D} $

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