The number of electrons with the azimuthal quantum number $l=1$ 1nd $l=2$ in ground state of $_{24}Cr$ is respectively :

Question

$\begin{array}{1 1}(a)\;16\;and\;5\\(b)\;12\;and\;5\\(c)\;16\;and\;4\\(d)\;12\;and\;4\end{array}$