A bag contains 3 black, 3 white and 2 red balls. One by one three balls are drawn without replacement. The probability that the third ball is red is equal to

Question

$\begin {array} {1 1} (A)\;\large\frac{3}{56} & \quad (B)\;\large\frac{1}{56} \\ (C)\;\large\frac{12}{56} & \quad (D)\\large\frac{14}{56} \end {array}$