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Questions  >>  JEEMAIN and NEET  >>  Mathematics  >>  Class12  >>  Probability
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Q)

Twelve tickets are numbered from 1 to 12. One tickets is drawn at random, then the probability of the number to be divisible by 2 or 3 is

$\begin {array} {1 1} (A)\;\large\frac{2}{3} & \quad (B)\;\large\frac{7}{12} \\ (C)\;\large\frac{5}{6} & \quad (D)\;\large\frac{3}{4} \end {array}$

 

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