A polariser and an analyser are oriented so that maximum light is transmitted of intensity $I_0$ What will be the intensity of the out coming light when analyer is rotated through $60^{\circ}$

Question

$(a)\;\frac{I_0}{2} \\ (b)\;\frac{I_0}{4} \\ (c)\;\frac{\sqrt 3 I_0 }{2} \\ (d)\;\frac{3 I_0}{4}$