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Q)

$ ^{\sim}(p \wedge q)$ is equivalent to

$\begin {array} {1 1} (A)\;(^{\sim}p)V q & \quad (B)\;(^{\sim}p)V (^{\sim}q) \\ (C)\;(^{\sim}p)\wedge (^{\sim}q) & \quad (D)\;(p) V (^{\sim}q) \end {array}$

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