$^{\sim}(p \wedge q)$ is equivalent to

Question

$\begin {array} {1 1} (A)\;(^{\sim}p)V q & \quad (B)\;(^{\sim}p)V (^{\sim}q) \\ (C)\;(^{\sim}p)\wedge (^{\sim}q) & \quad (D)\;(p) V (^{\sim}q) \end {array}$