(A)(x−5)ˆi−(y+4)ˆj−(z−6)ˆk=λ(3ˆi+7ˆj+2ˆk)(B)(x−5)ˆi+(y+4)ˆj+(z−6)ˆk=λ(3ˆi+7ˆj+2ˆk)(C)(x−5)ˆi−(y+4)ˆj+(z−6)ˆk=−λ(3ˆi+7ˆj+2ˆk)(D)(x−5)ˆi+(y+4)ˆj+(z−6)ˆk=λ(3ˆi−7ˆj−2ˆk)