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A hydrogen like atom (atomic No. Z) is in a higher excited state of quantam number n. This excited atom can make a transition to the first excited state by successively emitting two photons of energies 10.20 eV and 17.00 eV respectively. alternatively the atom from the same excited state can make a transition to the second excited state by successively emitting two photons of energy 4.25eV and 5.95 eV respectively. Determine the values of n and Z.

$(a)\; n=6,z = 3\qquad(b)\;n=3,z=6\qquad(c)\;n=2,z=5\qquad(d)\;n=4,n=2$

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