The formula for calculating the Highest Oxidation State for a Transition metal can be given as follows: Number of Unpaired d-electrons + Two s-orbital electrons. This is true for all the transition metals except two. Which of the following two?

Question

$\begin{array}{1 1} \text{Copper and Chromium} \\ \text{Copper and Scandium } \\ \text{Zinc and Scandium} \\ \text{Chromium and Zinc} \end{array}$