Find the value of $\lambda$, so that lines $\large \frac{1-x}{3}=\frac{7y-14}{2\lambda}=\frac{5z-10}{11}$ and $\large \frac{7-7x}{3\lambda}=\large\frac{y-5}{1}=\frac{6-z}{5}$ are perpendicular to each other.

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