If $x^2+y^2=t-\large\frac{1}{t} ,$$x^4+y^4 =t^2+\large\frac{1}{t^2}$ then $\large\frac{dy}{dx}$

Question

$(a)\;\frac{1}{xy^3} \\ (b)\;\frac{1}{x^3y} \\ (c)\;\frac{-1}{xy^3} \\ (d)\;\frac{-1}{x^3y}$