General solution of differential equation : $x^2e^y dy - (x-1) e^x dx=0$

Question

$(a)\;e^x=\frac{e^y}{x}+c \\ (b)\;e^y=\frac{e^x}{x}+c \\ (c)\;e^x= \frac{e^y}{y}+c \\ (d)\;e^y= \frac{e^x}{y}+c$