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Let $g(n) $ is a continuous differential function which takes positive value for $ x \leq 0$ and satisfy $\int \limits_0^2 g(t) dt = x \sqrt {g(x)} $ with $f(1) =V_2$. find the value of $f(\sqrt 2 +1)$

$(a)\;\frac{1}{4} \\ (b)\;4 \\ (c)\;\sqrt 2 +1 \\ (d)\;\sqrt 2 -1 $

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