$\large\frac{dy}{dx}$$=(4x+y+1)^2$ if $dy(0)=1$

Question

$(a)\;4x+y+1= 2\tan (2x+\frac{\pi}{4}) \\ (b)\;4x+y+1= 2\tan (x+\frac{\pi}{4}) \\ (c)\;4x+y+1= 2 \cot (x+\frac{\pi}{4}) \\ (d)\;4x+y+1= 2 \cot (2x+\frac{\pi}{4}) $