If p is the length of the perpendicular from the origin to the line $\large\frac{x}{a}+\frac{y}{6}$$=1$ then $\large\frac{1}{a^2}+\frac{1}{b^2}$=?

Question

$\begin{array}{1 1}(a)\;\large\frac{1}{p^2}&(b)\;p^2\\(c)\;0&(d)\;1\end{array}$