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JEEMAIN and NEET
>>
Physics
>>
Class12
>>
Electrostatic Potential and Capacitance
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Q)
A particle with kinetic energy
10
M
e
V
and charge
4
e
is heading towards a stationary nucleus of atomic number 100 . Calculate the distance of closest approach ?
(
a
)
5.76
×
10
−
14
m
(
b
)
57.6
×
10
−
14
m
(
c
)
0.576
×
10
−
14
m
(
d
)
N
o
n
e
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